X^2-(5/3)x+(25/36)=0

Solution for X^2-(5/3)x+(25/36)=0 equation:

X^2-(5/3)X+(25/36)=0


Domain of the equation: 3)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X^2-(+5/3)X+(+25/36)=0

We multiply parentheses

X^2-5X^2+(+25/36)=0

We get rid of parentheses

X^2-5X^2+25/36=0

We multiply all the terms by the denominator


X^2*36-5X^2*36+25=0

Wy multiply elements

36X^2-180X^2+25=0

We add all the numbers together, and all the variables

-144X^2+25=0

a = -144; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-144)·25
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-144}=\frac{-120}{-288}
=5/12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-144}=\frac{120}{-288}
=-5/12
$